VibeMathedMath problems solved with AI

The Abhyankar-Sathaye embedding conjecture

A polynomial f∈C[z1,…,zn]f\in\mathbb C[z_1,\dots,z_n] is a coordinate if it is the first component of a polynomial automorphism of An\mathbb A^n. The Abhyankar-Sathaye (epimorphism, or embedding) conjecture asserts that if C[z1,…,zn]/(f)≅C[n−1]\mathbb C[z_1,\dots,z_n]/(f)\cong\mathbb C^{[n-1]} then ff is a coordinate; geometrically, every hypersurface embedding An−1↪An\mathbb A^{n-1}\hookrightarrow\mathbb A^n is rectifiable. For n=2n=2 this is the Abhyankar-Moh-Suzuki theorem; Sathaye and Russell treated planes linear in one variable, and Kaliman-Venereau-Zaidenberg and Maubach handled four-variable equations a(x)y+b(x,z,t)a(x)y+b(x,z,t). Is every polynomial whose zero locus is isomorphic to affine (n−1)(n-1)-space a coordinate?

Result
Disproved(see note)
Status
Candidate (review pending)
AI contribution
AI-discovered
Method
Construction
Field
Affine algebraic geometry; polynomial automorphisms
Posed by
S. S. Abhyankar and A. Sathaye; the coordinate question is distinguished in A. Sathaye, On linear planes, Proc. Amer. Math. Soc. 56 (1976)
Year posed
1976
Years open
50y
Solved
2026-09-24
Model
Unreleased internal OpenAI model
Vendor
OpenAI
Collaborators
—
Verification
Lean-checked, statement unaudited
Publication
Announced
Collection
OpenAI math release (October 2026), version adc7f12
Significance
45 / 100
Disclosed cost
—
Wikipedia
No dedicated article

What was actually shown

Theorem 1.1: an explicit F∈C[h,u,v,w]F\in\mathbb C[h,u,v,w], built from a perturbed cusp parametrisation, has C[h,u,v,w]/(F)≅C[3]\mathbb C[h,u,v,w]/(F)\cong\mathbb C^{[3]} but a critical point on the fibre F=−1F=-1, so FF is not a coordinate; adjoining variables gives counterexamples for every n≥4n\ge4. The 5 October companion gives a degree-five ff in four variables with every fibre isomorphic to A3\mathbb A^3 and no fibre rectifiable, so the conjecture fails even for polynomials with all fibres affine. Not shown: the case n=3n=3 (whether every embedded affine plane in A3\mathbb A^3 is rectifiable), which stays open.

What the AI did

Produced by an unreleased internal OpenAI model as part of an OpenAI evaluation on open research problems, published in the openai/math release (pinned commit adc7f12). The release README says the vast majority of results used one fixed procedure, averaging about three hours of ChatGPT Pro thinking compute per result; this result is not among the README's stated exceptions (the Riemann zeta zero-free region work and the Hodge conjecture for CM abelian varieties). The manuscript is authored as OpenAI with no human author named. The main theorem has a Lean formalization in the release (Comparator challenge AbhyankarSathaye); a later family manuscript (5 October 2026) gives a stronger example with every fibre affine three-space.

Verification

No independent mathematician has checked this yet. Checked here: abstract, introduction and Theorem 1.1 of the TeX source, read against the conjecture as stated via Sathaye, Kraft and Blanc-van Santen. Lean-checked on the release's Comparator challenge AbhyankarSathaye (declaration OAI.AbhyankarSathaye.exists_noncoordinate_polynomial, listed in lean/formalization.yaml). Its statement was read here: for every n≥4n\ge4 there is F∈C[x1,…,xn]F\in\mathbb C[x_1,\dots,x_n] with a C\mathbb C-algebra isomorphism from the quotient by (F)(F) to a polynomial ring in n−1n-1 variables, and no C\mathbb C-algebra automorphism sends a variable to FF. That is the headline, for all n≥4n\ge4. Not rebuilt here. The paper states the three-variable case is not addressed. The explicit degree-five polynomial of the 5 October companion (all fibres affine) is unformalized.

Sources

Changelog1 change

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