Albertson–Berman Induced Forest Conjecture
Albertson and Berman conjectured that for every simple planar graph on vertices, the largest vertex set inducing a forest has size at least . The standing lower bound since the same year has been Borodin's , from his acyclic five-colour theorem. False: there is an explicit -vertex simple -connected maximal planar graph whose largest induced forest has exactly vertices, and an infinite family on vertices with induced-forest number exactly , giving the ratio even for triangulations of minimum degree five.
- Result
- Disproved(see note)
- Status
- Resolved
- AI contribution
- AI co-developed
- Method
- Construction
- Field
- Graph theory
- Posed by
- Michael O. Albertson, David M. Berman
- Year posed
- 1979
- Years open
- 47y
- Solved
- 2026-08-11
- Model
- GPT-5.6 Sol
- Vendor
- OpenAI
- Collaborators
- Heejae Jung
- Verification
- Site-confirmed
- Publication
- Preprint
- Significance
- 30 / 100
- Disclosed cost
- —
- Wikipedia
- Not counted (article postdates the solution)
What was actually shown
The ratio 15/31 is not claimed to be optimal, and the paper makes no claim that 31 vertices is the smallest possible counterexample. The construction produces separating triangles by design, so it says nothing about the 4-connected case.
What the AI did
The paper's "Acknowledgments and AI disclosure" section states that the two-terminal gadget "was discovered, and substantial parts of the proof strategy were developed, through interaction with OpenAI GPT-5.6 Sol", while the author "selected the research problem, directed the computational search and subsequent proof development, and checked the resulting mathematical arguments and computational certificates". GPT-5.6 Sol also assisted in preparing the manuscript and the verification code.
Verification
Reproduced here on 12 August 2026. The refutation is a single finite object, so it is checkable outright rather than on trust. The 31-vertex seed was rebuilt from the paper's own definitions - the 14-vertex gadget's cyclic neighbour lists, the pentagonal-bipyramid base, the decorated rim edges, the stated labelling and the two completion edges - without running the author's code. That yields a simple 3-connected planar graph on 31 vertices with edges, hence a triangulation, with the paper's degree multiset . Its maximum induced forest was then computed exactly by two independent algorithms: an ILP with lazy cycle-elimination cuts, and a branch-and-bound minimum feedback vertex set with no LP involved. Both give , equivalently a minimum feedback vertex set of exactly 16, against the 15.5 the conjecture requires. The two finite inputs to the symbolic argument were separately brute-forced - the terminal profile over all internal subsets, and over all subsets of the core - and for confirmed planar on vertices with edges, minimum degree five, every seed induced. Worth noting what the shipped verifier does not do: it certifies the gadget embedding, the profile, and the sphere certificates, but never computes or , and says so. That computation is the one this site supplied. Not peer-reviewed, not on arXiv, no independent expert review.
Sources
- PaperA 15/31 Counterexample Family to the Albertson-Berman ConjecturePreprint PDF
- CodeAuthor's verification script
- Independent workMakarov - a preprint claiming a somewhat different counterexample found independently without AIMakarov - preprint PDF
- Problem recordMohar's open problem list: induced forests in planar graphs
- OtherMakarov, Large induced forests in planar multigraphs - calls the conjecture open, revised 9 Aug 2026
Submitted by MellowWalrus138 on
The ratio has been improved to 25/52, and there is no counterexample on fewer than 29 vertices.
https://arxiv.org/abs/2608.23260