VibeMathedMath problems solved with AI

Is block sensitivity at most quadratic in spectral sensitivity? (Aaronson, Ben-David, Kothari, Rao and Tal)

For a total Boolean function f:{0,1}n→{0,1}f:\{0,1\}^n\to\{0,1\}, the spectral sensitivity λ(f)\lambda(f) is the largest eigenvalue of the adjacency matrix of its sensitivity graph (the hypercube edges across which ff changes value), and the block sensitivity bs(f)\mathrm{bs}(f) is the largest number of disjoint blocks of bits each of whose flip changes ff at some input. Huang's proof gives deg⁡(f)≤λ(f)2\deg(f)\le\lambda(f)^2, and with Nisan-Szegedy bs(f)=O(λ(f)4)\mathrm{bs}(f)=O(\lambda(f)^4). Aaronson, Ben-David, Kothari, Rao and Tal asked: is bs(f)=O(λ(f)2)\mathrm{bs}(f)=O(\lambda(f)^2)?

Result
Disproved(see note)
Status
Candidate (review pending)
AI contribution
AI co-developed
Method
Construction
Field
Boolean function complexity; sensitivity
Posed by
Scott Aaronson, Shalev Ben-David, Robin Kothari, Shravas Rao and Avishay Tal, Degree vs. approximate degree and quantum implications of Huang's sensitivity theorem (STOC 2021), Section 7
Year posed
2020
Years open
6y
Solved
2026-08-01
Model
GPT-5.6-Sol (ideas); Claude Opus 5 with Harmonic's Aristotle (Lean)
Vendor
OpenAI; Anthropic; Harmonic
Collaborators
Alexander Meiburg
Verification
Lean-checked, statement unaudited
Publication
Preprint
Significance
22 / 100
Disclosed cost
—
Wikipedia
No dedicated article

What was actually shown

Theorem 6.1: a total Boolean function on 2,017,584 variables with bs(f)≥14011\mathrm{bs}(f)\ge14011 and λ(f)≤89.0162\lambda(f)\le89.0162, so bs(f)≥λ(f)2.127\mathrm{bs}(f)\ge\lambda(f)^{2.127}; composition gives a family with λ→∞\lambda\to\infty and bs=Ω(λ2.127)\mathrm{bs}=\Omega(\lambda^{2.127}), so no quadratic bound holds. The function is a union of subcubes indexed by a doubly regular tournament with gates fixed by the Lovász local lemma. An exponent near 2.20 on 1,255 variables is numerical evidence only. The true exponent, between 2.127 and 4, stays open. Since λ(f)≤s(f)\lambda(f)\le s(f), OpenAI's later disproof of bs=O(s2)\mathrm{bs}=O(s^2) (25 September 2026), which adapts this gated-tournament construction, implies this result.

What the AI did

The paper's Note on AI Usage: "Several key ideas of the proof, in particular that 'gated tournaments' would be a good candidate for large bs relative to lambda, were suggested by GPT-5.6-Sol. The initial proposed construction was on 269 variables. All text in this paper was produced without generative AI tooling, and the author is responsible for the exposition, minimizing and optimizing size and parameters, and verifying the faithfulness of the Lean formalization." The paper says the formalization was carried out using Aristotle; the repository's formalization.yaml records a Claude Code session on Claude Opus 5 with about a dozen goal-level human turns, plus Harmonic's prover for leaf lemmas.

Verification

Checked here on 7 October 2026: Theorem 6.1 and Corollary 6.2 of arXiv:2608.00851 were read against the question as printed in Section 7 of Aaronson, Ben-David, Kothari, Rao and Tal. In Timeroot/BS_Lam, BSLambda/Main.lean was read: exists_bs_gt_lam_rpow states a total Boolean function on ZMod 14011 x Fin 144 inputs with λ(f)2.12<bs(f)\lambda(f)^{2.12}<\mathrm{bs}(f) (the comparator challenge printed in the paper's Appendix B), and exists_ratio_blowup states (14011/U)mλ(Fm)2≤bs(Fm)(14011/U)^m\lambda(F_m)^2\le\mathrm{bs}(F_m) for the mm-fold self-compositions, with 14011/U>114011/U>1, which is the unbounded-ratio disproof. The definitions of bs, the sensitivity-graph adjacency matrix and its top eigenvalue match the paper. The repository reports no sorry and only propext, Classical.choice and Quot.sound, and proves the multiplicativity of λ\lambda under composition rather than importing it. Not rebuilt here; no CI run is published.

Sources

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