Gaussian product inequality conjecture
Let be a centered Gaussian vector, not necessarily nondegenerate. Then, for every , Moreover, if for every , then equality holds if and only if are independent.
- Result
- Proved
- Status
- Resolved
- AI contribution
- AI-discovered
- Method
- Argument
- Field
- Probability & statistics
- Posed by
- Péter E. Frenkel
- Year posed
- 2007
- Years open
- 19y
- Solved
- 2026-07-20
- Model
- ChatGPT 5.6 Sol
- Vendor
- —
- Collaborators
- Frédéric Ouimet, Dylan Greaves
- Verification
- Lean-verified
- Publication
- Announced
- Significance
- 20 / 100
- Disclosed cost
- —
- Wikipedia
- No dedicated article
What the AI did
The AI provided a complete and correct solution without the characterization of equality in terms of independence (but only because the equality case was not in the original prompt by Dylan Greaves).
Verification
The prompt and output are available at https://chatgpt.com/share/6a5ea69b-1648-83e8-80b1-014ae0b1003c. This early version of the proof was formalized in Lean using Codex; see https://github.com/dylgre/gaussian-product-inequality. The proof has also been checked by ChatGPT 5.6 Sol (Pro), Gemini 3.1 Pro (Extended Thinking), Grok 4.5 (Expert), and Frédéric Ouimet.
Source
A proof of the strong Gaussian product inequality conjecture
Submitted by JollyJackal127