VibeMathedMath problems solved with AI

Phangara's conjecture: every order-six S-Hadamard matrix is equivalent to Tao's cubic matrix

Lisonek (2019) called a complex Hadamard matrix HH an S-Hadamard matrix if its entrywise square H∘2H^{\circ2} is also Hadamard. Tao's cubic matrix of order six, with cube-root-of-unity entries, is an example. Phangara (MSc thesis, Simon Fraser University, 2026, Conjecture 3.1.6) conjectured that it is the only one in order six. Is every S-Hadamard matrix of order six equivalent, under row and column permutations and unit phase multiplications, to Tao's cubic matrix?

Result
Proved(see note)
Status
Candidate (review pending)
AI contribution
AI-discovered
Method
Argument
Field
Complex Hadamard matrices; S-Hadamard matrices
Posed by
Jasleen Phangara (Conjecture 3.1.6, MSc thesis, Simon Fraser University, 2026)
Year posed
2026
Years open
0y
Solved
2026-09-24
Model
Unreleased internal OpenAI model
Vendor
OpenAI
Collaborators
—
Verification
Unreviewed
Publication
Announced
Collection
OpenAI math release (October 2026), version adc7f12
Significance
5 / 100
Disclosed cost
—
Wikipedia
No dedicated article

What was actually shown

Proposition 3.1: if HH and its entrywise square are both complex Hadamard matrices of order six, then HH is equivalent to Tao's cubic matrix; in particular all its dephased entries are cube roots of unity. The manuscript notes that uniqueness of the cube-root class was already known from Butson classifications (Lampio-Ostergard-Szollosi; Liang-Chen-Long-Qiu); the new step derives cube-root entries from the two Hadamard conditions for arbitrary phases. It says nothing about other orders.

What the AI did

The release README says every result in openai/math was produced by an unreleased internal OpenAI model with a fixed procedure, on average about three hours of ChatGPT Pro thinking compute per result. This result is not one of the README's two exceptions (the Hodge conjecture for CM abelian varieties and the Re(s) > 11/12 zero-free region). The manuscript is authored 'OpenAI' and names no human author. The result is Proposition 3.1 of the companion Fourier-certificate manuscript, used there as a lemma.

Verification

No independent mathematician has checked this yet. Checked here: Proposition 3.1 of the manuscript was read against Phangara's conjecture as the manuscript quotes it; it states that if HH and H∘2H^{\circ2} are order-six Hadamard matrices then HH is equivalent to Tao's matrix. The proof is a short Newton-identity argument on row ratios. The Lean challenge HadamardCubeFiber formalizes only a supporting cancellation lemma (lean/docs/266.md says so), not this classification, so the entry is Unreviewed. The thesis itself was not opened here.

Source

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