VibeMathedMath problems solved with AI

The quasi-Riemann hypothesis: a fixed zero-free half-plane for zeta and all Dirichlet L-functions

The quasi-Riemann hypothesis asks for one gap that works at every height: is there a fixed σ0<1\sigma_0<1 such that the Riemann zeta function has no zeros in the half-plane ℜs>σ0\Re s>\sigma_0? Since Hadamard and de la Vallee Poussin (1896) it has been known that ζ(s)≠0\zeta(s)\ne0 on ℜs=1\Re s=1, but every known zero-free region shrinks toward that line as the height grows. The uniform version over all Dirichlet characters asks for a single σ0<1\sigma_0<1, independent of the modulus qq, the character χ\chi and the height, such that no L(s,χ)L(s,\chi) vanishes in ℜs>σ0\Re s>\sigma_0 (the pole of the principal character at s=1s=1 aside). Does such a σ0\sigma_0 exist?

Result
Proved(see note)
Status
Candidate (review pending)
AI contribution
AI-discovered
Method
Argument
Field
Analytic number theory
Posed by
Classical; the name is used by Billington, Cheng, Schettler and Suriajaya (2025), and the uniform Dirichlet form appears in Friedlander and Goldston (1997)
Year posed
—
Years open
—
Solved
2026-09-30
Model
Unreleased internal OpenAI model
Vendor
OpenAI
Collaborators
—
Verification
Lean-checked, statement unaudited
Publication
Announced
Collection
OpenAI math release (October 2026), version adc7f12
Significance
85 / 100
Disclosed cost
—
Wikipedia
No dedicated article

What was actually shown

Theorem 1 claims that every finite-order Hecke LL-function over Q(−3)\mathbb Q(\sqrt{-3}) and every Dirichlet LL-function, including ζ(s)\zeta(s), has no zero in ℜs>7/8\Re s>7/8, the principal pole at s=1s=1 excepted. So the nontrivial zeros of ζ\zeta have real part at most 7/87/8, and any exceptional real zero in (7/8,1)(7/8,1) is excluded. The proof runs through cubic theta series and sextic large sieves, first reaching 11/1211/12 and then refining to 7/87/8; the Dirichlet case is transferred from the Hecke family. It does not prove the Riemann hypothesis or GRH, and says so; the boundary line ℜs=7/8\Re s=7/8 is not covered. A separate manuscript gives a different proof of the weaker half-plane ℜs>11/12\Re s>11/12.

What the AI did

The release README says every manuscript in the collection was produced by an unreleased internal OpenAI model, and that the vast majority were obtained by one fixed procedure averaging about three hours of ChatGPT Pro thinking compute per result. It names the zero-free region for the Riemann zeta function as an exception to that fixed procedure, without saying what was done instead, and says the write-up of the companion Re(s) > 11/12 proof was human edited for readability. The manuscripts are credited to OpenAI with no human author named.

Verification

No independent mathematician has checked this yet. The statement of Theorem 1 was read against the posed question: it asserts exactly a fixed half-plane Re s > 7/8, uniform over all Dirichlet characters and over finite-order Hecke characters of Q(sqrt(-3)). The release's formalization.yaml lists three main results for this manuscript: OAI.riemannZeta_ne_zero_of_seven_eighths_lt_re, OAI.DirichletCharacter.LFunction_ne_zero_of_seven_eighths_lt_re and the Hecke analogue. The zeta and Dirichlet comparator statements are short and use Mathlib's own riemannZeta and DirichletCharacter.LFunction, so they state the headline claim with the principal pole excluded; the Hecke statement builds its own character and L-function definitions in a 245-line statement file, which were not audited here. Permitted axioms are propext, Quot.sound and Classical.choice. Not rebuilt here. The README marks this result as an exception to the release's fixed procedure. The corollaries (least nonresidues, square roots mod p) are not in the Lean statements.

Sources

Changelog1 change

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