VibeMathedMath problems solved with AI

A power saving in the Furstenberg-Sarkozy theorem (square-difference-free sets)

Let s(N)s(N) be the largest size of a set A⊆{1,…,N}A\subseteq\{1,\ldots,N\} with no two elements differing by a nonzero perfect square. Answering a question of Lovasz, Furstenberg and Sarkozy proved s(N)=o(N)s(N)=o(N). Quantitative bounds improved through Pintz-Steiger-Szemeredi and Bloom-Maynard to Green and Sawhney's s(N)≪Nexp⁡(−clog⁡N)s(N)\ll N\exp(-c\sqrt{\log N}), while Ruzsa-type constructions give s(N)≫N0.7334s(N)\gg N^{0.7334}. Green and Sawhney asked whether a fixed power saving holds. Is there an absolute c>0c>0 with s(N)≪N1−cs(N)\ll N^{1-c}?

Result
Proved(see note)
Status
Candidate (review pending)
AI contribution
AI-discovered
Method
Argument
Field
Additive combinatorics; Furstenberg-Sarkozy theorem
Posed by
B. Green and M. Sawhney, New bounds for the Furstenberg-Sarkozy theorem (arXiv:2411.17448), Section 1.1; the underlying problem originates with Lovasz
Year posed
2024
Years open
2y
Solved
2026-09-24
Model
Unreleased internal OpenAI model
Vendor
OpenAI
Collaborators
—
Verification
Lean-checked, statement unaudited
Publication
Announced
Collection
OpenAI math release (October 2026), version adc7f12
Significance
50 / 100
Disclosed cost
—
Wikipedia
No dedicated article

What was actually shown

Theorem 1.1: absolute c>0c>0, CC with ∣A∣≤CN1−c|A|\le CN^{1-c} for every square-difference-free A⊆[N]A\subseteq[N]; consequently the square-difference graph on [N][N] has chromatic number at least C−1NcC^{-1}N^c. Companions: for an intersective hh of degree k≥2k\ge2, a power saving Oh(N1−ck)O_h(N^{1-c_k}) with exponent depending only on kk; and for hh with a unit root modulo every modulus, a power saving ChN1−chC_hN^{1-c_h} for differences h(p)h(p) at primes. The exponent is tiny and not computed, far from Ruzsa's lower-bound exponent 0.7330.733; the true exponent is not addressed.

What the AI did

Produced by an unreleased internal OpenAI model as part of the openai/math release (pinned commit adc7f12). The release README says results were produced by one fixed procedure averaging about three hours of ChatGPT Pro thinking compute each; this result is not among the README exceptions (the Hodge conjecture for CM abelian varieties and the Re(s) > 11/12 zero-free region). The manuscript is authored as OpenAI with no human author named. A Lean formalization accompanies it (Comparator challenge SquareDifference).

Verification

No independent mathematician has checked this yet. Checked here: abstract, introduction and Theorem 1.1 of the TeX source, read against Green and Sawhney's question as cited. Lean: Comparator challenge SquareDifference, declaration OAI.SquareDifference.power_saving. This challenge is not in lean/formalization.yaml; its JSON config and solution module exist at the pinned commit. Its statement was read here: there exist reals c>0c>0 and CC such that for every N≥1N\ge1 every finite set of integers A⊆[1,N]A\subseteq[1,N] with a−b≠m2a-b\ne m^2 for all a,b∈Aa,b\in A and m≥1m\ge1 has ∣A∣≤CN1−c|A|\le CN^{1-c}. That is exactly the headline. Not rebuilt here. The paper says the exponent is extremely small and not computed. The two 5 October companions (intersective polynomials, prime arguments) are not formalized; the prime-argument one depends on a companion zero-free half-plane theorem for Dirichlet L-functions.

Sources

Changelog1 change

Discussion