Supporting affine functionals for Entanglement of Formation
The paper disproves the assumption that finite-dimensionality and the convex-roof structure of Entanglement of Formation guarantee a global supporting affine functional at every bipartite state. It gives an explicit degenerate two-qubit state for which no Hermitian satisfies both and for every state . The construction uses the equivalence between existence of such a functional and Lipschitz lower semicontinuity of , together with Wootters’ formula.
- Result
- Disproved(see note)
- Status
- Resolved
- AI contribution
- AI co-developed
- Method
- Construction
- Field
- Entanglement theory
- Posed by
- A.S. Holevo and M.E. Shirokov
- Year posed
- —
- Years open
- —
- Solved
- 2026-08-27
- Model
- Claude Fable 5
- Vendor
- Anthropic
- Collaborators
- —
- Verification
- Site-confirmed
- Publication
- Preprint
- Significance
- 10 / 100
- Disclosed cost
- —
- Wikipedia
- No dedicated article
What was actually shown
For two qubits, the paper considers
,
where . This rank-2 state has no global supporting affine functional for Entanglement of Formation.
Setting , Wootters’ formula gives
.
Consequently,
,
so is not Lipschitz lower semicontinuous at . By the paper’s criterion, no global supporting affine functional exists there. Thus the claimed universal existence fails even for two qubits, although it remains true for nondegenerate finite-dimensional states.
What the AI did
From the abstract: "We use Wootters' formula and the help of Claude Fable 5 to find a state of the system for which the latter property does not hold." The authors had already reduced the existence of a global supporting affine functional to Lipschitz lower semicontinuity, and knew in principle that Wootters' two-qubit formula could yield a counterexample; what they did not have was a practical way to construct one. They report the model found such a state very quickly, and it is the state of Proposition 3.
AI-co-developed rather than AI-discovered, and the distinction is the tier's definition rather than a judgement call: this is a subproblem the authors formulated, inside a proof they set up, which the model solved. The surrounding theory - the equivalence criterion, the existence conditions, the Lipschitz bounds in finite and infinite dimensions - is the authors'.
Verification
Site-confirmed: the counterexample was re-derived here on 28 August 2026, in exact arithmetic, from the entry's statement rather than the paper's method. Wootters' concurrence was implemented from scratch and evaluated symbolically on and on .
Results. exactly. has exact closed form at each rational - at it is , which differs from by , the term with coefficient about , confirming the paper's expansion. The difference quotient evaluates to , , , and at : a factor of ten per two decades, so it grows like and diverges. is therefore not Lipschitz lower semicontinuous at , which by the paper's own criterion is exactly the failure claimed.
What this does not establish. The equivalence between a global supporting affine functional and Lipschitz lower semicontinuity is the paper's, and was not checked here; nor were the further existence conditions or the infinite-dimensional bounds. The paper is an unrefereed preprint (v1, 27 August 2026, quant-ph) with no independent review.
Source
- PaperarXiv
Submitted by VibeGene on