VibeMathedMath problems solved with AI

Dihedral Ramsey numbers of the alternating a-path versus K_b, for every a >= 4: 1 + (a-1)(b-1)

Rdih(Paalt,Kb)=1+(a1)(b1)R_{\mathrm{dih}}(P_a^{\mathrm{alt}}, K_b) = 1 + (a-1)(b-1) for all a4a \geq 4, b1b \geq 1 — the a4a \geq 4 slice of Conjecture 4.9 (Damnjanović–Đorđević, arXiv:2607.06817). Combined with the a=3a = 3 case (see sibling entry), this resolves Conjecture 4.9 in full for a3a \geq 3.

Result
Proved(see note)
Status
Resolved
AI contribution
AI-discovered
Method
Argument
Field
Permutational Ramsey theory
Posed by
Damnjanović–Đorđević (Conj 4.9)
Year posed
2026
Years open
0y
Solved
2026-08-13
Model
Claude Fable 5
Vendor
Anthropic
Collaborators
Verification
Site-confirmed
Publication
Preprint
Significance
8 / 100
Disclosed cost
Wikipedia
No dedicated article

What was actually shown

The dihedral case only, for every a4a \ge 4 and b1b \ge 1; the substance is the upper bound, which the source paper's own computations could not reach. Together with the sibling a = 3 entry this proves Conjecture 4.9's claim 1+(a1)(b1)1+(a-1)(b-1) for all a3a \ge 3; the conjecture's trivial a = 1, 2 cases are unaddressed by either entry, and the cyclic analogue Rcyc(Paalt,Kb)R_{cyc}(P_a^{alt}, K_b) for a4a \ge 4 remains open. The engine is a self-contained inequality of independent interest: for any graph on a linearly ordered vertex set, the alternating-path reach statistics satisfy m[P(m)+Q(m)]2E(G)\sum_m [P(m)+Q(m)] \ge 2|E(G)|, from which the theorem falls out by averaging and a pivot decomposition.

What the AI did

The proof was produced by a sealed, multi-agent research process: independently-launched Claude agents across three rounds, convergent results cross-validated. Two independent AI referee agents reviewed it dual-blind; both CONFIRMED. Human direction was limited to run design, operational supervision, and manual re-derivation of two write-up fixes.

Verification

Reproduced by this site on 13 August 2026, working from the pinned statement alone - the proof's machinery, both referee reports and the shipped CNFs were not consulted by the checker. Confirmed independently: the orbit anchor (Dih(a)|Dih(a)-orbit of Paalt=aP_a^{alt}| = a for a = 3..14); the Ramsey value at nine (a,b) cells in both directions - a good coloring exists at n=(a1)(b1)n = (a-1)(b-1) and none at n+1n+1 - exhaustively over every 2-coloring at (4,2), (5,2), (6,2), (7,2) and (4,3), and via an independently written CNF encoding solved with CaDiCaL at (8,2), (5,3), (6,3) and (4,4); and the proof's load-bearing inequality, the Aggregate Sum Theorem, by a third implementation built from the P/Q definitions rather than the recursion, over all 33,868 labeled graphs on up to six vertices - zero violations, minimum slack 0, so the bound is tight. The prose proof was also read here in full and every algebraic step traced. Not covered by the tier: the general argument has no human peer review - produced by a sealed multi-agent Claude run and refereed dual-blind by two AI agents in the same pipeline (both CONFIRMED; one non-fatal bug and one cosmetic slip found and repaired inline, originals kept). The Lean part is partial by its own declaration - four side lemmas, zero sorry or native_decide, standard axioms, source-audited here but not compiled (pinned v4.30.0 + Mathlib, no CI runs). The main theorems are not formalized; there, the referee reports and this site's checks are the verification.

Sources

Related entries

Submitted by ZestyWombat854 on

Changelog7 changes
  • StormyNarwhal118commented
  • Rasmus Lindahlchanged Short name from R_dih(P_a^alt, K_b) = 1+(a−1)(b−1), a≥4 to $R_{dih}(P_a^{alt},K_b)=1+(a-1)(b-1)$, $age4$
  • ZestyWombat854changed Model from Claude Fable to Claude Fable 5
  • Rasmus Lindahlchanged Verification from unreviewed to site-confirmed, also Related entries, Significance
  • Rasmus Lindahlapproved this entry
  • Rasmus Lindahlset Significance note to Resolves the dihedral side of a conjecture posed five weeks earlier in a single paper with…, also Verification note, What was actually shown
  • ZestyWombat854submitted this entry

Discussion1

StormyNarwhal11814 Aug 2026, 12:00 UTC

The bigger RdihR_{dih}, the greater the pleasure